CONTENTS

Exercise: Sum of Two Independent Poissons via CFs

Problem

A credit-risk model tracks defaults arriving at two independent intensities: investment-grade defaults N1Poisson(λ1)N_1 \sim \text{Poisson}(\lambda_1) and high-yield defaults N2Poisson(λ2)N_2 \sim \text{Poisson}(\lambda_2). Let N=N1+N2N = N_1 + N_2 be the total.

  1. Using CFs, show that NPoisson(λ1+λ2)N \sim \text{Poisson}(\lambda_1 + \lambda_2).

  2. Contrast with the case of non-independent N1,N2N_1, N_2. Suppose instead N1=N2=NN_1 = N_2 = N^* where NPoisson(λ)N^* \sim \text{Poisson}(\lambda). Compute φN1+N2(t)\varphi_{N_1 + N_2}(t) and show the result is not a Poisson CF. What distribution is N1+N2N_1 + N_2 in this case?
  3. Extension. In the independent case, given N1+N2=nN_1 + N_2 = n, what is the conditional distribution of N1N_1? Derive it using the CF of conditional distributions (or directly; the CF route is surprisingly clean).

Hint

Part 1 is almost immediate from the CF convolution rule. For part 2, N1+N2=2NN_1 + N_2 = 2N^* — no longer Poisson! For part 3, the conditional distribution given the sum is binomial.

Jump to the solution when you're ready.