CONTENTS

Solution: Sigma-Algebra Check

Collection A

FA={,Ω,{a,b},{c,d}}\mathcal{F}_A = \{\emptyset,\, \Omega,\, \{a,b\},\, \{c,d\}\}
  • Axiom 1: ΩFA\Omega \in \mathcal{F}_A. ✓
  • Axiom 2: {a,b}c={c,d}FA\{a,b\}^c = \{c,d\} \in \mathcal{F}_A; {c,d}c={a,b}FA\{c,d\}^c = \{a,b\} \in \mathcal{F}_A; Ωc=FA\Omega^c = \emptyset \in \mathcal{F}_A. ✓
  • Axiom 3: {a,b}{c,d}=ΩFA\{a,b\} \cup \{c,d\} = \Omega \in \mathcal{F}_A; all other unions stay within FA\mathcal{F}_A. ✓
FA\mathcal{F}_A is a sigma-algebra. It represents the coarse information "which pair did the outcome land in?" — identical in structure to the G\mathcal{G} example in the parent lesson.

Collection B

FB={,Ω,{a},{b,c,d},{a,b},{c,d}}\mathcal{F}_B = \{\emptyset,\, \Omega,\, \{a\},\, \{b,c,d\},\, \{a,b\},\, \{c,d\}\}
  • Axiom 1: ΩFB\Omega \in \mathcal{F}_B. ✓
  • Axiom 2: {a}c={b,c,d}FB\{a\}^c = \{b,c,d\} \in \mathcal{F}_B; {a,b}c={c,d}FB\{a,b\}^c = \{c,d\} \in \mathcal{F}_B. ✓
  • Axiom 3: {a}{c,d}={a,c,d}\{a\} \cup \{c,d\} = \{a,c,d\}. Is {a,c,d}FB\{a,c,d\} \in \mathcal{F}_B? No. ✗
FB\mathcal{F}_B is not a sigma-algebra. Axiom 3 fails: the union {a}{c,d}={a,c,d}\{a\} \cup \{c,d\} = \{a,c,d\} is not in FB\mathcal{F}_B.

Note also that axiom 2 would fail on {a,c,d}\{a,c,d\} if it were added, since its complement {b}\{b\} is also missing. Fixing a broken sigma-algebra usually requires adding several sets at once.

Collection C

FC={,Ω,{a},{b},{a,b},{c,d},{b,c,d},{a,c,d}}\mathcal{F}_C = \{\emptyset,\, \Omega,\, \{a\},\, \{b\},\, \{a,b\},\, \{c,d\},\, \{b,c,d\},\, \{a,c,d\}\}
  • Axiom 1: ΩFC\Omega \in \mathcal{F}_C. ✓
  • Axiom 2: {a}c={b,c,d}FC\{a\}^c = \{b,c,d\} \in \mathcal{F}_C; {b}c={a,c,d}FC\{b\}^c = \{a,c,d\} \in \mathcal{F}_C; {a,b}c={c,d}FC\{a,b\}^c = \{c,d\} \in \mathcal{F}_C. ✓
  • Axiom 3: {a}{b}={a,b}FC\{a\} \cup \{b\} = \{a,b\} \in \mathcal{F}_C; {a}{c,d}={a,c,d}FC\{a\} \cup \{c,d\} = \{a,c,d\} \in \mathcal{F}_C; {b}{c,d}={b,c,d}FC\{b\} \cup \{c,d\} = \{b,c,d\} \in \mathcal{F}_C. All other unions are Ω\Omega or already-listed sets. ✓
FC\mathcal{F}_C is a sigma-algebra. Notice it contains 8 sets but Ω=4|\Omega| = 4, so the power set has 24=162^4 = 16 elements — FC\mathcal{F}_C is a strict sub-sigma-algebra of the full power set. It represents the information "is aa the outcome?", "is bb the outcome?", and their combinations, but cannot distinguish cc from dd.

Takeaways

  • To verify a sigma-algebra, check all three axioms systematically. A single failure — even one missing complement — disqualifies the collection.
  • The smallest sigma-algebra on Ω\Omega is {,Ω}\{\emptyset, \Omega\}; the largest is the power set 2Ω2^\Omega. Everything in between represents some coarsening of information.
  • When a collection fails axiom 3, the fix is not just to add the missing union — you typically also need its complement (axiom 2), which may generate further required unions. The collection "generated" by a family of sets is the smallest sigma-algebra containing all of them.
Solution — Sigma-Algebra Check | q4quant.studio