CONTENTS

Exercise: Covariance Structure of Brownian Motion

Problem

Let (Wt)t0(W_t)_{t \ge 0} be a standard Brownian motion. Prove, using only the four axioms (BM1)–(BM4), that for all 0st0 \le s \le t:

Cov(Ws,Wt)=min(s,t)\operatorname{Cov}(W_s, W_t) = \min(s, t)

Then:

  1. Verify the identity numerically by simulation. Take s=0.3s = 0.3, t=0.7t = 0.7, generate N=105N = 10^5 sample paths of Brownian motion on [0,1][0, 1] using a grid of Δt=103\Delta t = 10^{-3}, and compute the sample covariance of (Ws,Wt)(W_s, W_t). Compare to the theoretical value min(s,t)=0.3\min(s, t) = 0.3.
  2. Using the covariance identity, compute Corr(Ws,Wt)\operatorname{Corr}(W_s, W_t) for 0<s<t0 < s < t. Show that the correlation depends only on the ratio s/ts/t, not on ss and tt separately.
  3. Use the correlation formula to explain why Brownian motion has long-range dependence in the sense that Corr(Ws,Wt)\operatorname{Corr}(W_s, W_t) does not vanish as the gap tst - s grows when both ss and tt grow proportionally.

Hint

For the proof, write Wt=Ws+(WtWs)W_t = W_s + (W_t - W_s) and use (BM2) and the mean-zero Gaussian increment from (BM3). For the simulation, use Wtk+1=Wtk+ΔtZkW_{t_{k+1}} = W_{t_k} + \sqrt{\Delta t}\,Z_k with ZkN(0,1)Z_k \sim \mathcal{N}(0, 1) i.i.d.

Jump to the solution when you're ready.