CONTENTS

Exercise: The Itô Correction — Why E[lnSt/S0]lnE[St/S0]\mathbb{E}[\ln S_t/S_0] \ne \ln \mathbb{E}[S_t/S_0]

Problem

Let StS_t follow geometric Brownian motion with drift μ\mu and volatility σ\sigma.

  1. Compute both E ⁣[ln(St/S0)]\mathbb{E}\!\left[\ln(S_t / S_0)\right] and lnE ⁣[St/S0]\ln\mathbb{E}\!\left[S_t / S_0\right] in closed form. Express the difference as a single clean quantity.
  2. Using the closed-form answers, argue via Jensen's inequality that the two quantities cannot be equal (unless σ=0\sigma = 0). Identify the convex function and the direction of the inequality.
  3. Explain what goes wrong if you "derive" GBM by naively applying the ordinary chain rule to lnSt\ln S_t (i.e. writing d(lnSt)=dSt/Std(\ln S_t) = dS_t/S_t without the Itô correction). Specifically, what would you conclude about E[ln(St/S0)]\mathbb{E}[\ln(S_t/S_0)]?
  4. A portfolio manager claims: "My fund has averaged 8% per year in log-returns over 20 years. By exponentiating, that translates to an arithmetic compound return of 8% per year for my investors." Is this claim correct? If not, what is the correct statement relating log-returns to arithmetic returns?

Hint

For parts 1 and 2: you already know ln(St/S0)N((μ12σ2)t,σ2t)\ln(S_t/S_0) \sim \mathcal{N}((\mu - \tfrac{1}{2}\sigma^2)t, \sigma^2 t) and E[St/S0]=eμt\mathbb{E}[S_t/S_0] = e^{\mu t}.

Jump to the solution when you're ready.