CONTENTS

Exercise: Variance Is a Submartingale — Doob's Decomposition

Problem

Let (Mn)(M_n) be a square-integrable martingale (E[Mn2]<\mathbb{E}[M_n^2] < \infty) with M0=0M_0 = 0.

  1. Using conditional Jensen's inequality, show that (Mn2)(M_n^2) is a submartingale. Identify precisely where the martingale property gets used versus the convexity of xx2x \mapsto x^2.

  2. Doob's decomposition. Any submartingale (Xn)(X_n) can be uniquely written as Xn=Yn+AnX_n = Y_n + A_n, where YnY_n is a martingale (Y0=X0Y_0 = X_0) and AnA_n is a predictable, non-decreasing process with A0=0A_0 = 0, defined by An=k=1nE[XkXk1Fk1].A_n = \sum_{k=1}^n \mathbb{E}[X_k - X_{k-1} \mid \mathcal{F}_{k-1}]. Verify this construction for Xn=Mn2X_n = M_n^2: compute AnA_n explicitly in terms of the conditional variance Var(MnMn1Fn1)\operatorname{Var}(M_n - M_{n-1} \mid \mathcal{F}_{n-1}).
  3. The process AnA_n in part 2 is called the predictable quadratic variation (or angle bracket) of MM, denoted Mn\langle M \rangle_n. Show that Mn=k=1nE[(MkMk1)2Fk1]\langle M\rangle_n = \sum_{k=1}^n \mathbb{E}[(M_k - M_{k-1})^2 \mid \mathcal{F}_{k-1}].
  4. Concrete case. For the symmetric random walk SnS_n with i.i.d. ±1\pm 1 increments, compute Sn\langle S\rangle_n. What is the submartingale Sn2S_n^2 and its martingale part Yn=Sn2SnY_n = S_n^2 - \langle S\rangle_n?

Hint

Conditional Jensen's inequality: for a convex function ϕ\phi, ϕ(E[XG])E[ϕ(X)G]\phi(\mathbb{E}[X \mid \mathcal{G}]) \le \mathbb{E}[\phi(X) \mid \mathcal{G}].

Jump to the solution when you're ready.