CONTENTS

Exercise: Why n\sqrt{n} Is the Right Rescaling for Donsker

Problem

Let Sn=i=1nXiS_n = \sum_{i=1}^{n} X_i be a simple symmetric random walk with Xi=±1X_i = \pm 1 i.i.d.

  1. Consider the rescaling Wn(α)(t):=nαSntW_n^{(\alpha)}(t) := n^{-\alpha} S_{\lfloor nt \rfloor} for t[0,1]t \in [0, 1]. Compute Var(Wn(α)(t))\operatorname{Var}(W_n^{(\alpha)}(t)) in the limit nn \to \infty for each of the three cases: α<1/2\alpha < 1/2, α=1/2\alpha = 1/2, and α>1/2\alpha > 1/2.
  2. Explain, using your answer to part 1, why each of the non-12\frac{1}{2} choices fails to produce a meaningful limit process.
  3. Under the α=1/2\alpha = 1/2 rescaling, what is Cov(Wn(1/2)(s),Wn(1/2)(t))\operatorname{Cov}(W_n^{(1/2)}(s), W_n^{(1/2)}(t)) for 0st10 \le s \le t \le 1 as nn \to \infty? Compare to the known covariance structure of Brownian motion.
  4. (Conceptual) In one sentence, explain why the dimensional argument "time scales as nn, space scales as n\sqrt{n}" follows directly from the variance formula Var(Sn)=n\operatorname{Var}(S_n) = n and nothing else about the underlying distribution.

Hint

For part 1, Var(Sn)=n\operatorname{Var}(S_n) = n so Var(nαSn)=n12α\operatorname{Var}(n^{-\alpha} S_n) = n^{1-2\alpha}. For part 3, use Cov(Sm,Sn)=min(m,n)\operatorname{Cov}(S_m, S_n) = \min(m, n), which follows from the independent-increments property.

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