CONTENTS

Exercise: Equivalent Measures and Lebesgue's Decomposition

Prerequisites: Radon-Nikodym Theorem

Problem

  1. Equivalent measures from normal shifts. For the normal-shift Radon-Nikodym derivative Z=exp(θXθ2/2)Z = \exp(\theta X - \theta^2/2) with XN(0,1)X \sim \mathcal{N}(0, 1) under P\mathbb{P}, show that:
    • Z>0Z > 0 everywhere, so PQ\mathbb{P} \ll \mathbb{Q} as well, hence PQ\mathbb{P} \sim \mathbb{Q}.
    • Compute dP/dQ=1/Zd\mathbb{P}/d\mathbb{Q} = 1/Z and verify EQ[1/Z]=1\mathbb{E}^{\mathbb{Q}}[1/Z] = 1.
  2. Non-equivalent example. Let P\mathbb{P} be the uniform distribution on [0,1][0, 1] and Q\mathbb{Q} be the uniform distribution on [0.5,1.5][0.5, 1.5] (both supported on subsets of R\mathbb{R}). Is QP\mathbb{Q} \ll \mathbb{P}? Is PQ\mathbb{P} \ll \mathbb{Q}? Is either absolutely continuous with respect to the other?
  3. Lebesgue decomposition. For P\mathbb{P} and Q\mathbb{Q} as in part 2, write Lebesgue's decomposition Q=Qac+Qsing\mathbb{Q} = \mathbb{Q}_{\text{ac}} + \mathbb{Q}_{\text{sing}} where QacP\mathbb{Q}_{\text{ac}} \ll \mathbb{P} and QsingP\mathbb{Q}_{\text{sing}} \perp \mathbb{P}. Identify the two components explicitly.
  4. Quant-finance interpretation. In the framework of risk-neutral pricing, the measure P\mathbb{P} (real-world) and Q\mathbb{Q} (risk-neutral) must be equivalent (same null sets) — not just absolutely continuous one way. Explain in one or two sentences why the equivalence condition matters: what financial catastrophe would it prevent if QP\mathbb{Q} \ll \mathbb{P} but not PQ\mathbb{P} \ll \mathbb{Q}?

Hint

For part 4, think about "impossible events" under Q\mathbb{Q} that are possible under P\mathbb{P} — or vice versa. Would a model that assigns zero probability to a possible adverse event be a good pricing model?

Jump to the solution when you're ready.