CONTENTS

Exercise: Computing qq in a Two-Period Binomial Tree

Problem

Consider a two-period binomial model with the following parameters:

  • Initial stock price S0=100S_0 = 100
  • Up factor u=1.1u = 1.1, down factor d=0.9d = 0.9 (so each period multiplies the price by uu or dd)
  • Each period has length Δt=0.5\Delta t = 0.5 years
  • Continuously compounded risk-free rate r=0.04r = 0.04 per year
  1. Compute the single-period risk-neutral probability qq such that erΔtEQ[St+ΔtSt]=Ste^{-r\Delta t}\mathbb{E}^{\mathbb{Q}}[S_{t+\Delta t} \mid S_t] = S_t.
  2. Draw (or write out) the tree of stock prices at times 00, Δt\Delta t, and 2Δt2\Delta t. Compute the risk-neutral probability of each terminal state.
  3. Price a European call with strike K=100K = 100 and maturity T=2Δt=1T = 2\Delta t = 1 year.
  4. Verify directly that under the real-world measure P\mathbb{P} with p=0.6p = 0.6, the discounted stock price is not a martingale — compute EP[erΔtSt+ΔtSt]\mathbb{E}^{\mathbb{P}}[e^{-r\Delta t}S_{t+\Delta t} \mid S_t] and compare it to StS_t.

Hint

For part 1, solve qu+(1q)d=erΔtq u + (1-q)d = e^{r\Delta t} for qq. For part 2, note that the up-up, up-down, down-up, and down-down states have risk-neutral probabilities q2q^2, q(1q)q(1-q), (1q)q(1-q)q, (1q)2(1-q)^2, and the middle two states both land at the same stock price S0udS_0 u d.

Jump to the solution when you're ready.